document.write( "Question 1203378: Find the area of the region enclosed by the graph of the equation $x^2-14x+3y+70=15+9y-y^2$ that lies below the line $y=x-3$. \n" ); document.write( "
Algebra.Com's Answer #838909 by Edwin McCravy(20062)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "First we get the equation x^2-14x+3y+70=15+9y-y^2 into standard form:\r\n" );
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document.write( "\"x%5E2-14x%2B3y%2B70=15%2B9y-y%5E2\"\r\n" );
document.write( "\"x%5E2-14x%2By%5E2%2B3y-9y=15-70\"\r\n" );
document.write( "\"x%5E2-14x%2By%5E2-6y=-55\"\r\n" );
document.write( "completing the square:\r\n" );
document.write( "\"%28x%5E2-14x%2B49%29%2B%28y%5E2-6y%2B9%29=-55%2B49%2B9\"\r\n" );
document.write( "\"%28x-7%29%5E2%2B%28y-3%29%5E2=3\"\r\n" );
document.write( "So it's a circle with center (7,3) and radius \"sqrt%283%29\"\r\n" );
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document.write( "Now we'll find the points of intersection with the line y = x-3:\r\n" );
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document.write( "\"x%5E2-14x%2By%5E2-6y=-55\"\r\n" );
document.write( "\"x%5E2-14x%2B%28x-3%29%5E2-6%28x-3%29=-55\"\r\n" );
document.write( "\"x%5E2-14x%2B%28x%5E2-6x%2B9%29-6x%2B18=-55\"\r\n" );
document.write( "\"x%5E2-14x%2Bx%5E2-6x%2B9-6x%2B18=-55\"\r\n" );
document.write( "\"2x%5E2-26x%2B27=-55\"\r\n" );
document.write( "\"2x%5E2-26x%2B82=0\"\r\n" );
document.write( "\"x+=+%28-%28-26%29+%2B-+sqrt%28%28-26%29%5E2-4%2A2%2A82+%29%29%2F%282%2A2%29+\"\r\n" );
document.write( "\"x+=+%2826+%2B-+sqrt%28676-656%29%29%2F%284%29+\"\r\n" );
document.write( "\"x+=+%2826+%2B-+sqrt%2820%29%29%2F%284%29+\"\r\n" );
document.write( "\"x+=+%2826+%2B-+sqrt%284%2A5%29%29%2F%284%29+\"\r\n" );
document.write( "\"x+=+%2826+%2B-+2sqrt%285%29%29%2F%284%29+\"\r\n" );
document.write( "\"x+=+%282%2813+%2B-+sqrt%285%29%29%29%2F%284%29+\"\r\n" );
document.write( "\"x+=+%2813+%2B-+sqrt%285%29%29%2F%282%29+\"\r\n" );
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document.write( "\"y=x-3\"\r\n" );
document.write( "\"y=%2813+%2B-+sqrt%285%29%29%2F%282%29-3\" \r\n" );
document.write( "\"y=%2813+%2B-+sqrt%285%29%29%2F%282%29-6%2F2\"\r\n" );
document.write( "\"y=%287+%2B-+sqrt%285%29%29%2F%282%29\"\r\n" );
document.write( "So the points of intersection are \r\n" );
document.write( "Let's graph the circle and line:\r\n" );
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document.write( "We want to find the major segment of the circle below the line.\r\n" );
document.write( "We now see that calculus is not the way to go here.  So we must\r\n" );
document.write( "resort to geometry and analytic geometry.  We draw a radius and\r\n" );
document.write( "a perpendicular to the chord, which forms a right triangle \r\n" );
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document.write( "We find the length of the green side of the right triangle. One end is\r\n" );
document.write( "the center of the circle (7,3).  The other end is the midpoint of the\r\n" );
document.write( "chord.  We find the midpoint of the chord:\r\n" );
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document.write( "\"expr%281%2F2%29%28x%5B1%5D%2Bx%5B2%5D%29\"\"%22%22=%22%22\"\"expr%281%2F2%29%28%2813+-+sqrt%285%29%29%2F%282%29%2B%2813+%2B+sqrt%285%29%29%2F%282%29%29\"\"%22%22=%22%22\"\"expr%281%2F2%29%2826%2F2%29\"\"%22%22=%22%22\"\"13%2F2\"\r\n" );
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document.write( "\"expr%281%2F2%29%28y%5B1%5D%2By%5B2%5D%29\"\"%22%22=%22%22\"\"expr%281%2F2%29%28%287+-+sqrt%285%29%29%2F%282%29%2B%287+%2B+sqrt%285%29%29%2F%282%29%29\"\"%22%22=%22%22\"\"expr%281%2F2%29%2814%2F2%29\"\"%22%22=%22%22\"\"7%2F2\"\r\n" );
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document.write( "So the midpoint of the chord is \"%28matrix%281%2C3%2C13%2F2%2C%22%2C%22%2C7%2F2%29%29\"\r\n" );
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document.write( "We use the distance formula to find the length of the green side\r\n" );
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document.write( "\"sqrt%28%287-13%2F2%29%5E2%2B%283-7%2F2%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%2814%2F2-13%2F2%29%5E2%2B%286%2F2-7%2F2%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%281%2F2%29%5E2%2B%28-1%2F2%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%281%2F4%2B1%2F4%29\"\"%22%22=%22%22\"\"sqrt%282%2F4%29\"\"%22%22=%22%22\"\"sqrt%282%29%2F2\"  \r\n" );
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document.write( "So the green leg of the right triangle is \"sqrt%282%29%2F2\" \r\n" );
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document.write( "We use the Pythagorean theorem to find the other leg of the right triangle,\r\n" );
document.write( "The hypotenuse is the radius of the circle \"sqrt%283%29\".\r\n" );
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document.write( "other leg = half of chord = \"sqrt%28sqrt%283%29%5E2-%28sqrt%282%29%2F2%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%283-2%2F4%29\"\"%22%22=%22%22\"\"sqrt%286%2F2-1%2F2%29\"\"%22%22=%22%22\"\"sqrt%285%2F2%29\"\"%22%22=%22%22\"\"sqrt%28%285%2A2%29%2F%282%2A2%29%29\"\"%22%22=%22%22\"\"sqrt%2810%29%2F2\"\r\n" );
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document.write( "So the area of the right triangle is\r\n" );
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document.write( "\"expr%281%2F2%29%28base%29%28height%29\"\"%22%22=%22%22\"\"expr%281%2F2%29%2A%28sqrt%2810%29%2F2%29%2A%28sqrt%282%29%2F2%29\"\"sqrt%2820%29%2F8\"\"%22%22=%22%22\"\"sqrt%284%2A5%29%2F8\"\"%22%22=%22%22\"\"2sqrt%285%29%2F8\"\"%22%22=%22%22\"\"sqrt%285%29%2F4\"\r\n" );
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document.write( "We find the angle between the red and green lines from\r\n" );
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document.write( "\"cos%28angle%29=%28sqrt%282%29%29%2F2%29%2F%28sqrt%283%29%29=0.4082482905\" \r\n" );
document.write( "\"angle=1.150261991\"\"radians\"\r\n" );
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document.write( "We now draw in the radius to the other point of intersection of the circle and the line:\r\n" );
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document.write( "This gives us another right triangle congruent to the other one.\r\n" );
document.write( "Now the angle on the minor segment is twice the angle above or\r\n" );
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document.write( "\"2%281.150261991%29\"\"radians\" or \"2.300523982\"\"radians\"\r\n" );
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document.write( "To find the angle of the major segment we subtract from \"2pi\"\r\n" );
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document.write( "\"2pi-2.300523982\"\"radians\"\"%22%22=%22%22\"\"3.982661325\"\"radians\"\r\n" );
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document.write( "The area of the sector = \"expr%281%2F2%29%28radius%29%28matrix%281%2C3%2Cangle%2Cin%2Cradians%29%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "\"expr%281%2F2%29%28sqrt%283%29%5E%22%22%29%283.982661325%29\"\"%22%22=%22%22\"\"3.449085882\"\r\n" );
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document.write( "Finally we add the area of the two right triangles:\r\n" );
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document.write( "\"3.449085882%2B2%2A%28sqrt%285%29%2F4%29\"\"%22%22=%22%22\"\"4.567119871\" square units\r\n" );
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document.write( "Edwin
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