document.write( "Question 1203384: \n" ); document.write( "
Algebra.Com's Answer #838899 by Theo(13342)\"\" \"About 
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cos(b) = 4/5
\n" ); document.write( "a similar triangle would be those values multiplied by a common factor.
\n" ); document.write( "we'll call the common factor x.
\n" ); document.write( "you then get:
\n" ); document.write( "cos(B) = 4x/5x
\n" ); document.write( "you are given that a = 70
\n" ); document.write( "since a = 4x, this means that x = 70/4 = 17.5.
\n" ); document.write( "your common factor is 17.5
\n" ); document.write( "you have:
\n" ); document.write( "a = 70
\n" ); document.write( "c = 5 * 17.5 = 87.5
\n" ); document.write( "you can use pythagorus to get a^2 + b^2 = c^2 which becomes 70^2 + b^2 = 87.5^2.
\n" ); document.write( "solve for b^2 to get b^2 = 87.5^2 - 70^2 = 2756.25
\n" ); document.write( "solve for b to get b = square root of 2756.25 = 52.5
\n" ); document.write( "if you givide that by x = 17.5, you get b = 3.\r
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\n" ); document.write( "\n" ); document.write( "you unit triangle is a 3,4,5 triangle.
\n" ); document.write( "b is equal to 3, a is equal to 4, c is equal to 5.
\n" ); document.write( "this is the triangle you get when the common factor is 1.
\n" ); document.write( "when you multiply by the common factor of 17.5, you get a 52.5, 70, 87.5 triangle.\r
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\n" ); document.write( "\n" ); document.write( "the triangles are similar, which means the corresponding angles are congruent and the corresponding sides are proportional.\r
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\n" ); document.write( "\n" ); document.write( "the triangle that i drew has A on the top left, B on the bottom right, and C on the bottom left.
\n" ); document.write( "a is the side opposite angle A, b ks the side opposite angle B, C is the side opposite angle C.
\n" ); document.write( "angle C is a right angle.\r
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