document.write( "Question 1203379: Hi
\n" ); document.write( "Leo and issac had 95 balls together. Leo gave away 3 more than issac. Issac was left with 5 fewer than the balls he gave away. Leo had 2 more balls left than issac. How many did Leo give away.
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Algebra.Com's Answer #838890 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "With a little bit of analysis, the problem can be solved using a single variable....

\n" ); document.write( "Let x = number Isaac gave away [the number the question asks for]

\n" ); document.write( "Then x-5 = number Isaac had left [he was left with 5 fewer than he gave away]

\n" ); document.write( "And x+3 = number Leo gave away [3 more than Isaac gave away]

\n" ); document.write( "And finally, 95-(x+(x-5)+(x+3)) = 97-3x = number Leo had left [the total number was 95]

\n" ); document.write( "Leo had left 2 more than Isaac:

\n" ); document.write( "\"97-3x=%28x-5%29%2B2\"
\n" ); document.write( "\"4x=100\"
\n" ); document.write( "\"x=25\"

\n" ); document.write( "ANSWER: Isaac gave away 25 balls

\n" ); document.write( "Solving the problem using a system of 3 equations with 3 variables, as both of the other tutors did, is good algebra; however, the work required to actually solve the problem is very often much easier if you take some time to analyze the problem to find how to set it up using a single variable.

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