document.write( "Question 1203375: For Open House in the year 2006, there were
\n" ); document.write( "60 tours. In the year 2010 there were 66
\n" ); document.write( "tours. Assuming this rate remains constant,
\n" ); document.write( "predict how many tours will be given in the
\n" ); document.write( "year 2024. Create an equation to represent
\n" ); document.write( "this situation and graph it.\r
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Algebra.Com's Answer #838881 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
60 in 2006
\n" ); document.write( "66 in 2010
\n" ); document.write( "since this is in linear equations, the rate is assumed to be a certain number per year.
\n" ); document.write( "1006 to 1020 is 4 years.
\n" ); document.write( "your rate is 6 tours divided by 4 years = 6/4 tours per year.
\n" ); document.write( "thaat's a growth of 1.5 tours per year.
\n" ); document.write( "in 2006 = 60
\n" ); document.write( "in 2007 = 61.5
\n" ); document.write( "in 2008 = 63
\n" ); document.write( "in 2009 = 64.5
\n" ); document.write( "in 1010 = 66
\n" ); document.write( "your equation will be y = 1.5x + 60
\n" ); document.write( "x = 0 is the same as the year 2006.
\n" ); document.write( "the graph would look like this.
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\n" ); document.write( "the graphing software is at https://www.desmos.com/calculator
\n" ); document.write( "in the year 2024, the number of tours will be 1.5 * (2024 - 2006) + 60 which is equal to 1.5 * 18 + 60 = 87 \n" ); document.write( "
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