document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203371>Question 1203371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rose garden is formed by joining a rectangle, and semi circle, as shown below. The rectangle is 20 feet long and 12 feet wide. Find the area of the garden. Use the value of 3.14 for pi, and do not round your answer. Be sure to include the correct unit and answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #838875 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=838875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "It depends if the diagram is this<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C400%2C-10%2C10%2C-10%2C10%2C%0D%0Aline%28-6%2C4%2C6%2C4%29%2C%0D%0Aline%286%2C4%2C6%2C-4%29%2C%0D%0Aline%286%2C-4%2C-6%2C-4%29%2C%0D%0Aline%28-6%2C-4%2C-6%2C4%29%2C%0D%0Aarc%286%2C0%2C8%2C8%2C-90%2C90%29%2C%0D%0Alocate%280%2C4%2C%2220+ft%22%29%2C%0D%0Alocate%28-5.5%2C0%2C%2212+ft%22%29%2C%0D%0Alocate%28-9.8%2C-8%2Cmatrix%281%2C2%2C%22Diagram%22%2C%22not%22%29%29%2C%0D%0Alocate%28-9.8%2C-8.7%2Cmatrix%281%2C2%2C%22to%22%2C%22scale%22%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "OR if it's this<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C400%2C-10%2C10%2C-10%2C10%2C%0D%0Aline%28-6%2C4%2C6%2C4%29%2C%0D%0Aline%286%2C4%2C6%2C-4%29%2C%0D%0Aline%286%2C-4%2C-6%2C-4%29%2C%0D%0Aline%28-6%2C-4%2C-6%2C4%29%2C%0D%0Aarc%280%2C4%2C12%2C12%2C-180%2C0%29%2C%0D%0Alocate%280%2C4%2C%2220+ft%22%29%2C%0D%0Alocate%28-5.5%2C0%2C%2212+ft%22%29%2C%0D%0Alocate%28-9.8%2C-8%2Cmatrix%281%2C2%2C%22Diagram%22%2C%22not%22%29%29%2C%0D%0Alocate%28-9.8%2C-8.7%2Cmatrix%281%2C2%2C%22to%22%2C%22scale%22%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If it's the 1st diagram, then the semicircular area is <BR>\n" );
document.write( "(1/2)*pi*r^2 = (1/2)*pi*6^2 = 18pi square feet.<BR>\n" );
document.write( "That approximates to 18pi = 18*3.14 = 56.52 square feet\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Add that onto the rectangular area of 12*20 = 240 square feet.<BR>\n" );
document.write( "240+56.52 = 296.52\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The total area in the 1st figure is approximately 296.52 square feet.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If on the other hand the diagram was the 2nd one I've shown above, then:<BR>\n" );
document.write( "semicircle area = (1/2)*pi*r^2 = (1/2)*pi*10^2 = 50pi = 50*3.14 = 157<BR>\n" );
document.write( "rectangular area = 12*20 = 240 \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "total approximate area = 240+157 = 397 square feet\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Both involve 240, but the difference is the semicircular area. <BR>\n" );
document.write( "</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );