document.write( "Question 115286: find two consecutive odd integers whose product is 15 more than three times their sum.\r
\n" ); document.write( "\n" ); document.write( "My guess is x(x+2)=3x+15, when I work this problem I have to use the quadratic formula to get an answer I don't think is correct, 1/2 +- square root of 15.\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "LeeAnn \n" ); document.write( "
Algebra.Com's Answer #83886 by ganesh(20)\"\" \"About 
You can put this solution on YOUR website!
Let x and x + 2 be two consecutive odd integers.
\n" ); document.write( "Their product is x (x+2)= x^2 + 2x.
\n" ); document.write( "Their sum is x + x + 2 = 2x + 2.
\n" ); document.write( "Three times their sum = 3 (2x + 2) = 6x + 6.
\n" ); document.write( "Given that, their product is 15 more than three times their sum.
\n" ); document.write( "This can be mathematically written as x^2 + 2x = 6x + 6 + 15.
\n" ); document.write( "Simplifying, we get x^2 - 4x -21 = 0.\r
\n" ); document.write( "\n" ); document.write( "Solve. \r
\n" ); document.write( "\n" ); document.write( "x^2 - 7x + 3x - 21 = 0
\n" ); document.write( "Or, x(x - 7) + 3(x - 7) = 0
\n" ); document.write( "Or, (x - 7) (x + 3) = 0
\n" ); document.write( "The solutions are x = 7, -3.\r
\n" ); document.write( "\n" ); document.write( "So, -3, -1 is a set of solution and 7,9 is another set of solution.\r
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