document.write( "Question 1203363: A truck with 48-in.-diameter wheels is traveling at 50 mi/h.\r
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document.write( "a.) Find the angular speed of the wheels in rad/min, *hint convert miles to inches & hours to minutes: \r
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document.write( "b.) How many revolutions per minute do the wheels make?
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Algebra.Com's Answer #838859 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "1 hour = 60 min \n" ); document.write( "5280 feet = 1 mile \n" ); document.write( "12 inches = 1 ft \n" ); document.write( "1 revolution = 48pi inches \n" ); document.write( "2pi radians = 1 revolution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 48pi refers to the circumference of the circle of diameter 48 inches. \n" ); document.write( "C = pi*diameter\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Each of those equivalences then form a fraction as shown in this long conversion string \n" ); document.write( " \n" ); document.write( "The placement of each item is to form the next set of cancellations as I'll describe below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There's a lot of cancellations going on. \n" ); document.write( "After the dust settles, we have \"radians\" up top and \"minutes\" in the bottom. \n" ); document.write( "Those are the only two units left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the values along the top: 50*1*5280*12*2pi = 6,336,000pi\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the values along the bottom: 1*60*1*1*48pi*1 = 2880pi\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We end up with \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer to part (a) is 2200 radians per minute\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=======================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll have this conversion string \n" ); document.write( " \n" ); document.write( "The key difference is we don't involve \"2pi radians = 1 rev\" at the very end. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we haven't multiplied by 2pi. We can divide the previous result 2200 rad/min by 2pi to get the rpm (revolutions per min)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "rpm = (rads per min)/(2pi) \n" ); document.write( "rpm = (2200)/(2pi) \n" ); document.write( "rpm = 350.14087480217 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I used the calculator's stored version of pi to get the most accuracy possible. \n" ); document.write( "If your teacher instructs you to use something like pi = 3.14, then be sure to do so. Round the final answer however your teacher instructs. \n" ); document.write( " \n" ); document.write( " |