document.write( "Question 115286: find two consecutive odd integers whose product is 15 more than three times their sum.\r
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document.write( "My guess is x(x+2)=3x+15, when I work this problem I have to use the quadratic formula to get an answer I don't think is correct, 1/2 +- square root of 15.\r
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document.write( "Thank you
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document.write( "LeeAnn \n" );
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Algebra.Com's Answer #83882 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find two consecutive odd integers whose product is 15 more than three times their sum. \n" ); document.write( "------------- \n" ); document.write( "Odd integers are always one more (or less) than even integers. \n" ); document.write( "--------------- \n" ); document.write( "1st odd integer: 2x+1 \n" ); document.write( "next odd integer:2x+3 \n" ); document.write( "------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "(2x+1)(2x+3)= 3[(2x+1)+(2x+3)] + 15 \n" ); document.write( "4x^2 + 8x + 3 = 12x+27 \n" ); document.write( "4x^2 -4x -24 = 0 \n" ); document.write( "x^2-x-6 = 0 \n" ); document.write( "(x-3)(x+2) = 0 \n" ); document.write( "x = 3 or x=-2 \n" ); document.write( "-------------------- \n" ); document.write( "If x=3 you get: \n" ); document.write( "2x+1 = 7 and 2x+3 = 9 \n" ); document.write( "-------------- \n" ); document.write( "If x = -2 you get: \n" ); document.write( "2x+1 = -3 and 2x+3 = -1 \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |