document.write( "Question 1203332: If sin(t)=2/3, and t is in quadrant II, find
\n" ); document.write( "cos(t), sec(t), csc(t), tan(t), cot(t).
\n" ); document.write( "

Algebra.Com's Answer #838805 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I'll use the greek letter \"theta\" (pronounced \"theta\") in place of t because theta is often used in trig.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sin(theta) = 2/3
\n" ); document.write( "sine = opposite/hypotenuse\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We could say
\n" ); document.write( "opposite = 2
\n" ); document.write( "hypotenuse = 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Draw a right triangle in quadrant Q2 (northwest quadrant)
\n" ); document.write( "The reference angle theta is placed in the bottom right corner of the triangle.
\n" ); document.write( "
\n" ); document.write( "The unknown side adjacent is labeled x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the pythagorean theorem
\n" ); document.write( "\"a%5E2%2Bb%5E2+=+c%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%5E2%2Bx%5E2+=+3%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4%2Bx%5E2+=+9\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+9-4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%285%29\" or \"x+=+-sqrt%285%29\"
\n" ); document.write( "I'll go with the negative version of x to indicate we're to the left of the y axis.
\n" ); document.write( "x < 0 in Q2\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Here's the updated diagram
\n" ); document.write( "
\n" ); document.write( "opposite = 2
\n" ); document.write( "adjacent = \"-sqrt%285%29\"
\n" ); document.write( "hypotenuse = 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "\"cos%28theta%29+=+adjacent%2Fhypotenuse+=+-sqrt%285%29%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28theta%29+=+opposite%2Fadjacent+=+2%2F%28-sqrt%285%29%29+=+-2sqrt%285%29%2F5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"csc%28theta%29+=+hypotenuse%2Fopposite+=+3%2F2\" (this is the reciprocal of sine)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"sec%28theta%29+=+hypotenuse%2Fadjacent+=+3%2F%28-sqrt%285%29%29+=+-3sqrt%285%29%2F5\" (this is the reciprocal of cosine)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29+=+adjacent%2Fopposite+=+-sqrt%285%29%2F2\" (this is the reciprocal of tangent)
\n" ); document.write( "
\n" ); document.write( "
\n" );