document.write( "Question 1203315: The Royal Fruit Company produces two types of fruit drinks. The first type is 20% pure fruit juice, and the second type is 70% pure fruit juice. The company is attempting to produce a fruit drink that contains 35% pure fruit juice. How many pints of each of the two existing types of drink must be used to make 50 pints of a mixture that is 35% pure fruit juice? \n" ); document.write( "
Algebra.Com's Answer #838765 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "35 pints of the 20% drink \n" ); document.write( "15 pints of the 70% drink\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = amount of the 20% juice (1st batch) \n" ); document.write( "50-x = amount of the 70% juice (2nd batch) \n" ); document.write( "Each amount is in pints. \n" ); document.write( "These two expressions add to 50 pints total.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.2x = amount of pure fruit from the 1st batch \n" ); document.write( "0.7(50-x) = 35-0.7x = amount of pure fruit from the 2nd batch\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "batch1+batch2 = (0.2x) + (35-0.7x) = 35-0.5x = total amount of pure fruit\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The goal is to make a 35% fruit drink, and the company wants 50 pints. \n" ); document.write( "Therefore, the company requires 0.35*50 = 17.5 pints of pure fruit. \n" ); document.write( "This leads us to the equation \n" ); document.write( "35-0.5x = 17.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's solve for x \n" ); document.write( "35-0.5x = 17.5 \n" ); document.write( "-0.5x = 17.5-35 \n" ); document.write( "-0.5x = -17.5 \n" ); document.write( "x = -17.5/(-0.5) \n" ); document.write( "x = 35 \n" ); document.write( "We'll need 35 pints of the 20% batch.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also we'll need 15 pints of the 70% batch because 50-x = 50-35 = 15. \n" ); document.write( " \n" ); document.write( " |