document.write( "Question 1203307: The ratio of the altitude of a zone to the diameter of the sphere on which it is 1:5. The area of the zone is 80 pi. Find the area of the sphere. \n" ); document.write( "
Algebra.Com's Answer #838764 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Surface area of a sphere: \r
\n" ); document.write( "\n" ); document.write( "\"A=4%2Api%2Ar%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "let altitude be \"h\" and diameter \"d\"
\n" ); document.write( "given ratio is \"1%3A5\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"h%2Fd=1%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=d%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"r=d%2F2+\"=> \"h=%28d%2F2%29%2F5=d%2F10\"\r
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\n" ); document.write( "\n" ); document.write( "The area \"A\" of a spherical zone can be calculated using the formula \r
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\n" ); document.write( "\n" ); document.write( "\"A=2%C3%8F%E2%82%ACrh+\"\r
\n" ); document.write( "\n" ); document.write( "where \"h+\"is the height of the spherical layer and \"r\" is the radius of the sphere.\r
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\n" ); document.write( "\n" ); document.write( "if the area of the zone is \"80pi\", we have\r
\n" ); document.write( "\n" ); document.write( "\"80pi=2pi%2Arh\"...simplify\r
\n" ); document.write( "\n" ); document.write( "\"40=rh\".....substitute \"h\"\r
\n" ); document.write( "\n" ); document.write( "\"40=r%28r%2F10%29\"\r
\n" ); document.write( "\n" ); document.write( "\"400=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28400%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=20\"\r
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\n" ); document.write( "\n" ); document.write( "then, surface area of a sphere is: \r
\n" ); document.write( "\n" ); document.write( "\"A=4%2Api%2A20%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"A=4%2Api%2A400\"\r
\n" ); document.write( "\n" ); document.write( "\"A=1600pi\"\r
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