document.write( "Question 1203307: The ratio of the altitude of a zone to the diameter of the sphere on which it is 1:5. The area of the zone is 80 pi. Find the area of the sphere. \n" ); document.write( "
Algebra.Com's Answer #838764 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Surface area of a sphere: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let altitude be \n" ); document.write( "given ratio is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "where \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the area of the zone is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then, surface area of a sphere is: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |