document.write( "Question 1203309: The area of a zone is 50.265 sq.cm. If the altitude of the zone is 2 cm, solve the surface area of the sphere. \n" ); document.write( "
Algebra.Com's Answer #838759 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Surface area of a sphere: \r
\n" ); document.write( "\n" ); document.write( "\"+A=4%2Api%2Ar%5E2\"\r
\n" ); document.write( "\n" ); document.write( "let altitude be \"+h+\"and diameter \"+d\"\r
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\n" ); document.write( "\n" ); document.write( "given: \r
\n" ); document.write( "\n" ); document.write( "\"+h=2cm\"\r
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\n" ); document.write( "\n" ); document.write( "The area of a spherical zone is \"+A=50.265cm%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "using the formula \"+A=2pi%2Arh\" where \"+h\" is the height of the spherical layer and \"+r\" is the radius of the sphere, substitute given\r
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\n" ); document.write( "\n" ); document.write( "\"+50.265cm%5E2=2pi%2Ar%2A2cm\" ....solve for \"r\"\r
\n" ); document.write( "\n" ); document.write( "\"+r=50.265cm%5E2%2F%282pi%2A2cm%29\".....simplify\r
\n" ); document.write( "\n" ); document.write( "\"+r=50.265cm%2F%284pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+r=50.265cm%2F%284pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+r=3.9999616072570596cm\"\r
\n" ); document.write( "\n" ); document.write( "\"+r=4cm\"\r
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\n" ); document.write( "\n" ); document.write( "then, surface area of a sphere is: \r
\n" ); document.write( "\n" ); document.write( "\"+A=4%2Api%2A%284cm%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"+A=4%2Api%2A16cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"+A=64pi%2Acm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"+A=201.062cm%5E2\"\r
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