document.write( "Question 1203312: The area of a zone is 50.265 sq. cm. if the altitude of the zone is 2 cm, solve the surface area of the sphere. \n" ); document.write( "
Algebra.Com's Answer #838756 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "According to Wolfram MathWorld,
\n" ); document.write( "https://mathworld.wolfram.com/Zone.html
\n" ); document.write( "A zone is like a partial bit of the sphere's surface. We can think of it like a small piece of an orange peel. That link marks the zone in blue.\r
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\n" ); document.write( "\n" ); document.write( "Here's another article talking about the topic
\n" ); document.write( "https://en.wikipedia.org/wiki/Spherical_segment
\n" ); document.write( "A spherical segment is a wedge-shaped 3D solid that forms after making those two parallel cuts of the sphere. The zone is then the outer surface area. \r
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\n" ); document.write( "\n" ); document.write( "On either page is the formula \"S+=+2%2Api%2AR%2Ah\"
\n" ); document.write( "pi = 3.14 approximately (use more decimal digits of pi to get better accuracy)
\n" ); document.write( "R = radius of the sphere
\n" ); document.write( "h = height aka altitude
\n" ); document.write( "S = surface area of the zone\r
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\n" ); document.write( "\n" ); document.write( "In this case we are given
\n" ); document.write( "S = 50.265
\n" ); document.write( "h = 2\r
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\n" ); document.write( "\n" ); document.write( "We'll use those items to find the radius R.
\n" ); document.write( "\"S+=+2%2Api%2AR%2Ah\"\r
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\n" ); document.write( "\n" ); document.write( "\"50.265+=+2%2A3.14%2AR%2A2\"\r
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\n" ); document.write( "\n" ); document.write( "\"50.265+=+12.56R\"\r
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\n" ); document.write( "\n" ); document.write( "\"R+=+%2850.265%29%2F%2812.56%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"R+=+4.00199045\" approximately\r
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\n" ); document.write( "\n" ); document.write( "Now we can determine the surface area of the sphere
\n" ); document.write( "\"SA+=+4%2Api%2AR%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"SA+=+4%2A3.14%2A4.00199045%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"SA+=+201.16005\" \r
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\n" ); document.write( "\n" ); document.write( "The surface area of the entire sphere is approximately 201.16005 square cm.\r
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\n" ); document.write( "\n" ); document.write( "In a real life example, this would be the entire orange peel (as opposed to the small piece of it mentioned earlier).
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