document.write( "Question 1203280: A father is 51 years old and his son is 19. How many years ago was the father 5 times his son’s age? \n" ); document.write( "
Algebra.Com's Answer #838720 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x and 5x represent their ages when the father was 5 times as old as his son. Then the difference in their ages then (and always) is 4x. \n" ); document.write( "Now their ages are 51 and 19, so the difference in their ages is 32. So \n" ); document.write( "4x = 32 \n" ); document.write( "x = 8 \n" ); document.write( "Their ages when the father was 5 times as old as his son were x = 8 and 5x = 40. \n" ); document.write( "Since their ages now are 51 and 19, that was 11 years ago. \n" ); document.write( "ANSWER: 11 \n" ); document.write( " \n" ); document.write( " |