document.write( "Question 1203275: (a) in how many ways can the letters of the word be arranged in a line?
\n" ); document.write( "(b) In how many ways can the arrangement begins with F and ends with 5? \n" ); document.write( "
Algebra.Com's Answer #838711 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "There are 9 choices in the first slot, then 8 for the next, and so on. \r
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\n" ); document.write( "\n" ); document.write( "9*8*7*6*5*4*3*2*1 = 362,880 different ways to arrange the letters of FACETIOUS.\r
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\n" ); document.write( "\n" ); document.write( "For more information, search out \"factorial\".\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "I'm assuming the \"5\" should be \"S\"\r
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\n" ); document.write( "\n" ); document.write( "We have F locked in the first slot and S locked in the last slot.\r
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\n" ); document.write( "\n" ); document.write( "There are 2 letters locked in place.
\n" ); document.write( "That leaves 9-2 = 7 letters left to arrange in 7 slots.\r
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\n" ); document.write( "\n" ); document.write( "7*6*5*4*3*2*1 = 5,040 different ways to arrange the letters of FACETIOUS such that the \"word\" begins with F and ends with S.
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