document.write( "Question 1203274: (a) In how many different ways can the letters in the word
\n" ); document.write( "ARRANGEMENTS be arranged?
\n" ); document.write( "(b) Find the number of ways the arrangement begins with the letters EE.
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Algebra.Com's Answer #838706 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "a) There are 12 letters, and if these were all unique, there would be 12! unique ways to arrange them. However, we must divide out the duplicate (non-distinct) arrangements. For this, we note there are 2 A's, 2 R's, 2 N's, and 2 E's, each of which contributes 2! non-distinct arrangements:\r
\n" ); document.write( "\n" ); document.write( " Number of unique arrangements = \"+12%21%2F+%282%21%2A2%21%2A2%21%2A2%21%29+\" = 29937600\r
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\n" ); document.write( "\n" ); document.write( "Part (b) can be done similarly. Since the arrangements begin with EE, that effectively leaves 10 letters to arrange, and you'll need to remove duplicates in a similar way as in part (a). It is as if the E's are removed and you repeat part (a) without the E's. \r
\n" ); document.write( "\n" ); document.write( "Hint: the answer will be 10! / (something) \n" ); document.write( "
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