document.write( "Question 1203260: Alonzo, Bob, and Casper work bussing tables at a restaurant. Alonzo has a 60% chance, Bob has a 10% chance, and Casper has a 30% chance of bussing tables in the middle area of the restaurant. If Alonzo is bussing tables, he has a 6% chance of breaking a dish. If Bob is bussing tables, he has a 2% chance of breaking a dish. Finally, if Casper is bussing tables, he has a 4% chance of breaking a dish. If there is a broken dish in the middle of the restaurant, what is the probability it was broken by Casper?\r
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\n" ); document.write( "\n" ); document.write( "Multiple Choice
\n" ); document.write( "0.012
\n" ); document.write( "0.040
\n" ); document.write( "0.240
\n" ); document.write( "0.720
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Algebra.Com's Answer #838680 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: Choice C) 0.240\r
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\n" ); document.write( "\n" ); document.write( "Explanation\r
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\n" ); document.write( "\n" ); document.write( "There are at least two methods we can use. \r
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\n" ); document.write( "\n" ); document.write( "Method 1\r
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\n" ); document.write( "\n" ); document.write( "A = Alonzo buses tables in the middle area
\n" ); document.write( "B = Bob buses tables in the middle area
\n" ); document.write( "C = Casper buses tables in the middle area
\n" ); document.write( "D = Dish is broken in the middle area
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\n" ); document.write( "\n" ); document.write( "From the second sentence of the instructions, we are given these 3 pieces of info:
\n" ); document.write( "P(A) = 0.60
\n" ); document.write( "P(B) = 0.10
\n" ); document.write( "P(C) = 0.30\r
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\n" ); document.write( "\n" ); document.write( "The next 3 sentences offer these additional 3 pieces of info:
\n" ); document.write( "P(D given A) = 0.06
\n" ); document.write( "P(D given B) = 0.02
\n" ); document.write( "P(D given C) = 0.04\r
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\n" ); document.write( "\n" ); document.write( "Goal: Compute P(C given D)
\n" ); document.write( "In other words, we want to find P(C) when we know event D has occurred. \r
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\n" ); document.write( "\n" ); document.write( "Use Bayes' Theorem
\n" ); document.write( "P(C given D) = P(D given C)*P(C)/P(D)\r
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\n" ); document.write( "\n" ); document.write( "We already have the values of P(D given C) and P(C)\r
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\n" ); document.write( "\n" ); document.write( "We'll need P(D)\r
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\n" ); document.write( "\n" ); document.write( "Use the Law of Total Probability
\n" ); document.write( "P(D) = P(D and A) + P(D and B) + P(D and C)
\n" ); document.write( "P(D) = P(D given A)*P(A) + P(D given B)*P(B) + P(D given C)*P(C)
\n" ); document.write( "P(D) = 0.06*0.60 + 0.02*0.10 + 0.04*0.30
\n" ); document.write( "P(D) = 0.05\r
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\n" ); document.write( "\n" ); document.write( "We have enough info to compute the following
\n" ); document.write( "P(C given D) = P(D given C)*P(C)/P(D)
\n" ); document.write( "P(C given D) = 0.04*0.30/0.05
\n" ); document.write( "P(C given D) = 0.012/0.05
\n" ); document.write( "P(C given D) = 12/50
\n" ); document.write( "P(C given D) = 6/25
\n" ); document.write( "P(C given D) = 0.240\r
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\n" ); document.write( "\n" ); document.write( "This is why the final answer is choice C\r
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\n" ); document.write( "\n" ); document.write( "Method 2\r
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\n" ); document.write( "\n" ); document.write( "Let's say that there are 1000 instances of a single dish being bused.\r
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\n" ); document.write( "\n" ); document.write( "Alonzo handles 60% of them, Bob does 10%, Casper does the remaining 30%
\n" ); document.write( "60% of 1000 = 0.60*1000 = 600
\n" ); document.write( "10% of 1000 = 0.10*1000 = 100
\n" ); document.write( "30% of 1000 = 0.30*1000 = 300\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "Alonzo buses 600 times
\n" ); document.write( "Bob buses 100 times
\n" ); document.write( "Casper buses 300 times\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Alonzo breaks a dish 6% of the time
\n" ); document.write( "6% of 600 = 0.06*600 = 36
\n" ); document.write( "If Alonzo buses 600 times then we expect him to break around 36 dishes.\r
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\n" ); document.write( "\n" ); document.write( "Bob breaks a dish 2% of the time
\n" ); document.write( "2% of 100 = 0.02*100 = 2
\n" ); document.write( "If Bob buses 100 times then we expect him to break around 2 dishes.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Casper breaks a dish 4% of the time
\n" ); document.write( "4% of 300 = 0.04*300 = 12
\n" ); document.write( "If Casper buses 300 times then we expect him to break around 12 dishes.\r
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\n" ); document.write( "\n" ); document.write( "An total estimate of 36+2+12 = 50 dishes have been broken.
\n" ); document.write( "P(D) = probability of a broken dish
\n" ); document.write( "P(D) = (50 dishes broken)/(1000 dishes total)
\n" ); document.write( "P(D) = 50/1000
\n" ); document.write( "P(D) = 0.05
\n" ); document.write( "This was calculated earlier in the previous section.\r
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\n" ); document.write( "\n" ); document.write( "Of those 50 broken dishes, Casper is estimated to break 12 of them.
\n" ); document.write( "12/50 = 0.240
\n" ); document.write( "If we encounter a broken dish, then there's a 24% chance that Casper did it.
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