document.write( "Question 1203245: Please help me solve this question, thank you!\r
\n" ); document.write( "\n" ); document.write( "The mean weight of loads of rock is 4.16 tons with a standard deviation of 1.68 tons.\r
\n" ); document.write( "\n" ); document.write( "If 14 loads are chosen at random for a weight check, find the probability (as percent) that the mean weight of those loads is NO less than 3.902 tons. Assume that the variable is normally distributed.\r
\n" ); document.write( "\n" ); document.write( "The probability is: %\r
\n" ); document.write( "\n" ); document.write( "(Round your answer to the nearest whole percent)
\n" ); document.write( "

Algebra.Com's Answer #838668 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
population mean is 4.16 tons
\n" ); document.write( "standard deviation is 1.68 tons
\n" ); document.write( "sample size is 14
\n" ); document.write( "standrd error is 1.68 / sqrt(14) = .449.
\n" ); document.write( "mean weight not less than 3.902 means mean weight greater than or equal to 3.902.
\n" ); document.write( "use of the same calculator used in the previous calculatgor gets you a probability of 0.7172 = 71.72% that the mean weight of the sample is not less than 3.902.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "here are the results of using that calculator.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );