document.write( "Question 1203245: Please help me solve this question, thank you!\r
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document.write( "The mean weight of loads of rock is 4.16 tons with a standard deviation of 1.68 tons.\r
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document.write( "If 14 loads are chosen at random for a weight check, find the probability (as percent) that the mean weight of those loads is NO less than 3.902 tons. Assume that the variable is normally distributed.\r
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document.write( "The probability is: %\r
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document.write( "(Round your answer to the nearest whole percent) \n" );
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Algebra.Com's Answer #838668 by Theo(13342)![]() ![]() You can put this solution on YOUR website! population mean is 4.16 tons \n" ); document.write( "standard deviation is 1.68 tons \n" ); document.write( "sample size is 14 \n" ); document.write( "standrd error is 1.68 / sqrt(14) = .449. \n" ); document.write( "mean weight not less than 3.902 means mean weight greater than or equal to 3.902. \n" ); document.write( "use of the same calculator used in the previous calculatgor gets you a probability of 0.7172 = 71.72% that the mean weight of the sample is not less than 3.902.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here are the results of using that calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |