document.write( "Question 1203243: Please show me how to solve this problem, thank you!\r
\n" ); document.write( "\n" ); document.write( "The average age of a vehicle registered in Canada is about 100 months and the standard deviation for the population is 19..\r
\n" ); document.write( "\n" ); document.write( "If a random sample of 33 vehicles is selected, find the probability (as percent) that the mean of their age is between 105 and 107 months.\r
\n" ); document.write( "\n" ); document.write( "The probability is: %
\n" ); document.write( "(Round your answer to the nearest whole percent)
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Algebra.Com's Answer #838648 by Theo(13342)\"\" \"About 
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mean of population is 100 months.
\n" ); document.write( "standard deviation of population is 19.
\n" ); document.write( "sample size is 33
\n" ); document.write( "since you are looking for the mean of the sample, use the standard error rather than the standard devition.
\n" ); document.write( "standard error = standard deviation / square root of sample size = 19 / sqrt(33) = 3.3075.
\n" ); document.write( "you want to know the probability that the mean age is between 105 and 107 months.
\n" ); document.write( "since you have the standard deviastion of the population, use the z-score.
\n" ); document.write( "that formula is z = (x-m)/s
\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the sample mean
\n" ); document.write( "m is the popultion mean.
\n" ); document.write( "s is the standard error.
\n" ); document.write( "for x = 105, the formula becomes z = (105 - 100) / 3.3075 = 1.626.
\n" ); document.write( "for x = 107, the formula becomes z = (107 - 100) / 3.3075 = 2.276.
\n" ); document.write( "the area to the left of z = 1.626 = .9480
\n" ); document.write( "the area to the left of z = 2.276 = .9886
\n" ); document.write( "the area in between is the larger area minus the smaller area = .0406.
\n" ); document.write( "that's the probability of getting a z-score between 1.6726 and 2.276.
\n" ); document.write( "that is also the probability of getting an average age between 105 and 107.\r
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\n" ); document.write( "\n" ); document.write( "using the z-score calculator at https://davidmlane.com/hyperstat/z_table.html, this is what the output looks like.\r
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\n" ); document.write( "\n" ); document.write( "you could use the z-score tables, but the use of the calculator is easier and allows for greater accuracy.
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