document.write( "Question 1203234: Let x represent the smaller number and y the larger number. The sum of the two numbers is 200. If the larger number is 8 less than triple the smaller number, what are the two numbers?\r
\n" ); document.write( "\n" ); document.write( "The sum of two numbers is 200. But I’m confused as to write if the larger number is 8 less than triple the
\n" ); document.write( "X=200-y -> x=200-178.05 smaller #
\n" ); document.write( "X=-y+200
\n" ); document.write( "Replace y with 178.05
\n" ); document.write( "X=-178.05+200
\n" ); document.write( "X=21.95
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #838632 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "x = smaller number
\n" ); document.write( "y = larger number\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x+y = 200 because the two numbers sum to 200\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"The larger number is 8 less than triple the smaller\" means
\n" ); document.write( "larger = 3*smaller - 8
\n" ); document.write( "y = 3x - 8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We can plug this into the first equation to solve for x
\n" ); document.write( "x+y = 200
\n" ); document.write( "x+y = 200
\n" ); document.write( "x+3x-8 = 200
\n" ); document.write( "4x-8 = 200
\n" ); document.write( "4x = 200+8
\n" ); document.write( "4x = 208
\n" ); document.write( "x = 208/4
\n" ); document.write( "x = 52\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "y = 3x-8
\n" ); document.write( "y = 3*52-8
\n" ); document.write( "y = 156-8
\n" ); document.write( "y = 148\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer: The two numbers are 52 and 148.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check: 52+148 = 200
\n" ); document.write( "
\n" ); document.write( "
\n" );