document.write( "Question 1200796: A normal population has a mean of $62 and standard deviation of $14. You select random samples of nine.
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document.write( "a. What is the probability that a sample mean is greater than $65? (Round z-value to 2 decimal places and final answer to 4 decimal places.)
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document.write( " What is the probability that a sample mean is less than $58? (Round z-value to 2 decimal places and final answer to 4 decimal places.)
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document.write( " What is the probability that a sample mean is between $58 and $65? (Round z-value to 2 decimal places and final answer to 4 decimal places.)
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document.write( "What is the probability that the sampling error ( x¯
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document.write( " − μ) would be $9 or more? That is, what is the probability that the estimate of the population mean is less than $53 or more than $71? (Round z-value to 2 decimal places and final answer to 4 decimal places.) \n" );
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Algebra.Com's Answer #838626 by Theo(13342) You can put this solution on YOUR website! population mean is 62. \n" ); document.write( "population standard deviation is 14. \n" ); document.write( "sample size is 9. \n" ); document.write( "standard error is standard deviation / sqrt(sample size) = 14 / sqrt(9) = 4.66667. \n" ); document.write( "round z-score to 2 decimal places. \n" ); document.write( "round probability to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula to use is z = (x-m)/s \n" ); document.write( "z is the z-score \n" ); document.write( "x is the sample mean \n" ); document.write( "m is the population mean \n" ); document.write( "s is the standard error that was derived from the population standard deviation divided by the square root of the sample size = 4.66667 as shown above.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a. What is the probability that a sample mean is greater than $65? (Round z-value to 2 decimal places and final answer to 4 decimal places.) \n" ); document.write( "What is the probability that a sample mean is less than $58? (Round z-value to 2 decimal places and final answer to 4 decimal places.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula becomes z = (58 - 62) / 4.66667 = -4 / 4.66667 = -.86. \n" ); document.write( "area to the left of that = .1949 ***** \n" ); document.write( "that's the probbility of getting a z-score less than -.86, which is the same as getting a sample mean less than 58.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What is the probability that a sample mean is between $58 and $65? (Round z-value to 2 decimal places and final answer to 4 decimal places.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "lower limit z = (58 - 62) / 4.66667 = -.86 \n" ); document.write( "high limit z = (65 - 62) / 4.66667 = .64 \n" ); document.write( "area to the left of z = -.86 = .1949 \n" ); document.write( "area to the left of z = .64 = .7389 \n" ); document.write( "area in between = .7389 minus .1949 = .5440 ***** \n" ); document.write( "that's the probability of getting a z-score between -.86 and .64, whiich is the same as getting a sample mean between 58 and 65.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What is the probability that the sampling error ( x¯ \n" ); document.write( "− μ) would be $9 or more? That is, what is the probability that the estimate of the population mean is less than $53 or more than $71? (Round z-value to 2 decimal places and final answer to 4 decimal places.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "lower z-score = (53 - 62) / 4.66667 = -1.93 \n" ); document.write( "higher z-score = (71 - 62) / 4.66667 = 1.93\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area to the left of z = -1.93 = .0268 \n" ); document.write( "area to the right of z = 1.93 = .0268 \n" ); document.write( "the probability of either getting a z-score less than -1.93 or greater than 1.93 = .0268 + .0268 = .0536. ***** \n" ); document.write( "that's the same as getting a sample mean less than 53 or greater than 71.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i confirmd these results through the use of the calculator at https://www.hackmath.net/en/calculator/normal-distribution?mean=0&sd=1&above=&below=&ll=-0.86&ul=0.64&area=outside&outsideLL=-1.93&outsideUL=1.93&draw=Calculate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here are the results from using the clculator.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |