document.write( "Question 1203227: Please help me solve this problem!Thanks!\r
\n" ); document.write( "\n" ); document.write( "Given a binomial distribution in which the probability of success is 0.53 and the number of trials is 14, what is the probability for each of the following:\r
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\n" ); document.write( "\n" ); document.write( "Getting exactly 12 successes?\r
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\n" ); document.write( "\n" ); document.write( "Getting more than 12 successes?\r
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\n" ); document.write( "\n" ); document.write( "Getting less than or equal to 12 successes?
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Algebra.Com's Answer #838617 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
p(x) = p^x * q^(n-x)*c(n,x)\r
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\n" ); document.write( "\n" ); document.write( "n = 14
\n" ); document.write( "x = 0 to 14
\n" ); document.write( "p = .53
\n" ); document.write( "q = 1 minus p = .47\r
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\n" ); document.write( "\n" ); document.write( "probability of getting exactly 12 successes is p(12) = .53^12 * .47^(14-12) * c(14,12) = 0.009875237.\r
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\n" ); document.write( "\n" ); document.write( "probability of getting more than 12 successes is equal to p(13) + p(14) = 0.001713216 + 0.000137995 = .001851211.\r
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\n" ); document.write( "\n" ); document.write( "probability of getting less than or equal to 12 successes is 1 minus the probability of getting more than 12 successes is equal to 1 minus p(13) minus p(14) = 1 minus 0.001713216 minus 0.000137995 = .998148789.\r
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\n" ); document.write( "\n" ); document.write( "here's what it looks like in excel.\r
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\n" ); document.write( "\n" ); document.write( "total probbility is equal to 1, as it should.\r
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