document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115234>Question 115234</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395771188/algebrahomeworkh>Algebra and trigonometry structure and method</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "how much pure antifreeze must be added to 12L of a 40% solution of antifreeze to obtain a 60& solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83854 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .4*12+1X=.6(12+X)<BR>\n" );
document.write( "4.8+X=7.2+.6X<BR>\n" );
document.write( "X-.6X=7.2-4.8<BR>\n" );
document.write( ".4X=2.4<BR>\n" );
document.write( "X=2.4/.4<BR>\n" );
document.write( "X=6 LITERS OF PURE ANTIFREEZE MUST BE ADDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".4*12+6=.6(12+6)<BR>\n" );
document.write( "4.8+6=.6*18<BR>\n" );
document.write( "10.8=10.8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );