document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115254>Question 115254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a ladder is resting against a wall. the top of the ladder touches the wall at the height of 18 ft. find the length of the ladder if the length is 6 ft more than its distance from the wall  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83853 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> HERE YOU HAVE A RIGHT TRIANGLE WITH SIDE=18 FEET & THE HYPOTENUSE=BASE+6.<BR>\n" );
document.write( "A^2+B^2=C^2<BR>\n" );
document.write( "18^2+B^2=(B+6)^2 <BR>\n" );
document.write( "324+B^2=B^2+12B+36<BR>\n" );
document.write( "12B=324-36<BR>\n" );
document.write( "12B=288<BR>\n" );
document.write( "B=288/12<BR>\n" );
document.write( "B=24 IS THE LENGTH FROM THE FOOT OF THE LADDER TO THE BUILDING.<BR>\n" );
document.write( "24+6=30 FEET IS THE LENGTH OF THE LADDER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "18^2+24^2=30^2<BR>\n" );
document.write( "324+576=900<BR>\n" );
document.write( "900=900<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );