document.write( "Question 1203160: How do I go about setting up this equation?\r
\n" ); document.write( "\n" ); document.write( "2 trains are a mile and a 1/2 apart\r
\n" ); document.write( "\n" ); document.write( "A is traveling at 3/4ths the speed of train B\r
\n" ); document.write( "\n" ); document.write( "they'll collide in 4 1/2 minutes\r
\n" ); document.write( "\n" ); document.write( "how fast is each train going\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance.
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Algebra.Com's Answer #838502 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
How do I go about setting up this equation?\r
\n" ); document.write( "\n" ); document.write( "2 trains are a mile and a 1/2 apart\r
\n" ); document.write( "\n" ); document.write( "A is traveling at 3/4ths the speed of train B\r
\n" ); document.write( "\n" ); document.write( "they'll collide in 4 1/2 minutes\r
\n" ); document.write( "\n" ); document.write( "how fast is each train going
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\n" ); document.write( "The fact that they'll collide implies they're moving toward each other, so the speeds are added.
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\n" ); document.write( "A = 0.75B
\n" ); document.write( "A + B = 1.75B (the \"closing speed\")
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\n" ); document.write( "d = r*t
\n" ); document.write( "1.5 = 1.75B*4.5
\n" ); document.write( "B = 1.5/(1.75*4.5) = 1/5.25 miles/minute
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\n" ); document.write( "A = 0.75B = 1/7 miles/minute
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\n" ); document.write( "Multiply by 60 to get miles per hour
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