document.write( "Question 1202007: A box contains 10 flash drives. 5 flash drives are second hand and contain data. 2 flash drives a randomly chosen from the box. X is equal to 1 if atleast one of the flash drives chosen already contains data, otherwise X is 0.
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Algebra.Com's Answer #838497 by ikleyn(52781)\"\" \"About 
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document.write( "X = 0, if both selected flash drives are second hand. \r\n" );
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document.write( "       The probability for it is  P(X=0) = \"%285%2F10%29%2A%284%2F9%29\" = \"%281%2F2%29%2A%284%2F9%29\" = \"2%2F9\".\r\n" );
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document.write( "Otherwise, X = 1 with the probability P(X=1) = 1 - \"2%2F9\" = \"7%2F9\".\r\n" );
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document.write( "It is the binomial distribution probability: n= 1 (the number of trials);\r\n" );
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document.write( "                                             p= \"2%2F9\" for X= 0  (successful trial) and  p= \"7%2F9\" for X= 1 (unsuccessful trial).\r\n" );
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