document.write( "Question 1203136: Eunice is three times old as Mavis.The sum of their age is 60.How old is each\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #838449 by ikleyn(52890) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "Eunice is three times $\"highlight%28as%29\"$ old as Mavis. The sum of their $\"highlight%28cross%28age%29%29\"$ ages is 60. How old is each
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Let M be the Mavis age.\r\n" );
document.write( "\r\n" );
document.write( "Then the Eunice age is 3M, according t the problem.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Next, from the problem, we have this equation\r\n" );
document.write( "\r\n" );
document.write( "    M + 3M = 60.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It gives\r\n" );
document.write( "\r\n" );
document.write( "     4M   = 60,  M = 60/4 = 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  Mavis is 15 years old; Eunice is 3*15 = 45 years old.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );