document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203134>Question 1203134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is drawn so that the width is 2 feet shorter than the length. The area of the rectangle is 3 square feet. Find the length of the rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #838445 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=838445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area = length * width = 3<BR>\n" );
document.write( "length = x and width = x - 2<BR>\n" );
document.write( "area = x * (x - 2) = x^2 - 2x = 3<BR>\n" );
document.write( "subtract 3 from both sides of that equation to get x^2 - 2x - 3 = 0.<BR>\n" );
document.write( "factor to get (x - 3) * (x + 1) = 0<BR>\n" );
document.write( "solve for x to get x = 3 or x = -1<BR>\n" );
document.write( "x has to be positive, so x = 3<BR>\n" );
document.write( "length = 3<BR>\n" );
document.write( "width = 1<BR>\n" );
document.write( "length = 3 is your solution.<BR>\n" );
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