document.write( "Question 1061532: Nora leaves Town A and walks towards Town B at a speed of 100m/min. At the same time , Kate and Lixin walk from Town B towards Town A at a speed of 80mm/min and 75m/min respectively. If Nora meets Lixin 6 minutes after passing Kate, find the distance between Town A and Town B.\r
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document.write( "Please help me this one!! I need it now!! Thank you. \n" );
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Algebra.Com's Answer #838390 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I will assume that Kate's rate is in fact 80 m/min and not 80 mm/min....! \n" ); document.write( "Nora and Kate together, walking at rates of 100 m/min and 80 m/min, cover the whole distance in a certain amount of time. \n" ); document.write( "Let t be the number of minutes it takes Nora and Kate to meet. Then the distance between the two towns is 180t. \n" ); document.write( "In the time it takes Nora and Kate to meet, Nora and Lixin together, traveling at rates of 100 m/min and 75 m/min, cover a distance of 175t. \n" ); document.write( "The fraction of the total distance between the two towns that Nora and Lixin together cover in t minutes is 175t/180t = 35/36. So the fraction of the total distance remaining to be covered for Nora and Lixin to meet is 1/36. \n" ); document.write( "The additional time required for Nora to meet Lixin is 6 minutes, so the time needed for Nora and Lixin to meet is 36*6 = 216 minutes. \n" ); document.write( "The combined speed of Nora and Lixin is 175 m/min, so the distance between the two towns is 216*175 = 37800 m. \n" ); document.write( "ANSWER: 37800 m \n" ); document.write( "As a check, note that the distance between the two towns can also be calculated as the amount of time Nora and Kate travel before meeting times their combined rate. The two of them met after 216-6 = 210 minutes, so.... \n" ); document.write( "210*180 = 37800 \n" ); document.write( " \n" ); document.write( " |