document.write( "Question 1061532: Nora leaves Town A and walks towards Town B at a speed of 100m/min. At the same time , Kate and Lixin walk from Town B towards Town A at a speed of 80mm/min and 75m/min respectively. If Nora meets Lixin 6 minutes after passing Kate, find the distance between Town A and Town B.\r
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Algebra.Com's Answer #838376 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Nora leaves Town A and walks towards Town B at a speed of 100m/min. At the same time , Kate and Lixin walk from Town B towards Town A at a speed of 80mm/min and 75m/min respectively. If Nora meets Lixin 6 minutes after passing Kate, find the distance between Town A and Town B.\r\n" );
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document.write( "Please help me this one!! I need it now!! Thank you.\r\n" );
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document.write( "----- what is written at this line and below it, is written/added by me, tutor @ikleyn -----\r\n" );
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document.write( "        I added it here, because the solution by tutor @MathTherapy is incorrect.\r\n" );
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document.write( "        So, I simply copied-pasted the solution by @MathTherapy and pointed/commented\r\n" );
document.write( "        that place, which is incorrect.\r\n" );
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document.write( "  <<<---===  this equation is INCORRECT  (mine, @ikleyn's comment)\r\n" );
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document.write( "It is written (it is valid) under the assumption that only Nora is moving, while Kate stands unmoved; but it is not so. Therefore, everything that follows in the @MathTherapy post, is invalid.\r\n" );
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document.write( "I know the tutor @MathTherapy as very accurate tutor at this forum.\r\n" );
document.write( "Dear @Math Therapy, if you decide to take off your post, may be, it will be the best decision - I will not have any objections against it.\r\n" );
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document.write( "Because my greatest goal is to keep this forum as clean as possible (as I can).\r\n" );
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document.write( "By the way, my original (very old, ~ 10 years ago) solution to this problem \r\n" );
document.write( "is the post number 1 in this bunch of posts.\r\n" );
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document.write( "So, had I place these my notes under my old solution, the chance would be great \r\n" );
document.write( "that nobody sees it. It is why I placed my notes here . . . \r\n" );
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document.write( "You're right, @IKLEYN. I did the problem as though it had stated, \"If Nora takes 6 mins\r\n" );
document.write( "to GET to the POINT where Lixin was when Nora and Kate MET,\" instead of, \"If Nora meets\r\n" );
document.write( "Lixin 6 minutes after passing Kate........\" \r\n" );
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document.write( "I EDITED the post, and REPOSTED the CORRECT solution!\r\n" );
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document.write( "Let time taken for Kate to meet Nora, and vice versa, be T\r\n" );
document.write( "Since Nora left Town A and Kate and Lixin left Town B at the same time, distance Nora covered, when she met Kate = 100T\r\n" );
document.write( "Also, distance Kate covered, when she met Nora, coming from Town B = 80T\r\n" );
document.write( "When Nora and Kate met, both had covered the entire distance between Towns A & B\r\n" );
document.write( "Therefore, distance between Towns A & B = 100T + 80T = 180T\r\n" );
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document.write( "At the same time that Nora and Kate met, Lixim, coming from Town B, had covered a distance of 75T\r\n" );
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document.write( "When Nora met Kate, Nora had traveled a distance of 100T. After meeting Kate, Nora then traveled an additional 6(100),\r\n" );
document.write( "or 600 m for a total of 100T + 600 m, when she and Lixin met \r\n" );
document.write( "Likewise, when Nora met Kate, Lixin had traveled a distance of 75T. 6 minutes thereafter, Lixin traveled an additional\r\n" );
document.write( "6(75), or 450 m for a total of 75T + 450 m, when she and Nora met \r\n" );
document.write( "Therefore, when Nora met Lixin, both had traveled a combined 100T + 600 + 75T + 450, the distance between the 2 towns\r\n" );
document.write( "And, since the distance between the 2 towns is 180T, we get: 100T + 600 + 75T + 450 = 180T\r\n" );
document.write( "                                                                       175T + 1,050 = 180T \r\n" );
document.write( "                                                                              1,050 = 180T - 175T\r\n" );
document.write( "                                                                              1,050 = 5T\r\n" );
document.write( "            Time taken for Nora and Kate to meet/Lixim to cover 75T, or  mins\r\n" );
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document.write( "Thus, distance between Towns A & B = 180T, or 180(210) = 37,800 m \n" );
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