document.write( "Question 114860: A bicycle leaves town at 16 mph at 8 am. A car leaves at 11 am, traveling in the same direction at 40 mph. How many minutes after 11 am is it when the car overtakes the bicycle? \n" ); document.write( "
Algebra.Com's Answer #83836 by ankor@dixie-net.com(22740)\"\" \"About 
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A bicycle leaves town at 16 mph at 8 am. A car leaves at 11 am, traveling in the
\n" ); document.write( " same direction at 40 mph. How many minutes after 11 am is it when the car
\n" ); document.write( " overtakes the bicycle?
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\n" ); document.write( "Let t = travel time (in hrs) of the car when it overtakes the bike
\n" ); document.write( "Then
\n" ); document.write( "(t+3) = travel time of the bike
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\n" ); document.write( "We know that when this happens, they will have traveled the same distance.
\n" ); document.write( "Make a distance equation from this fact: Distance = Speed * time
\n" ); document.write( ":
\n" ); document.write( "Car dist = Bike dist
\n" ); document.write( "40t = 16(t+3)
\n" ); document.write( "40t = 16t + 48
\n" ); document.write( "40t - 16t = 48
\n" ); document.write( "24t = 48
\n" ); document.write( "t = 48/24
\n" ); document.write( "t = 2 hrs
\n" ); document.write( ":
\n" ); document.write( "To answer the question, 120 minutes after 11
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\n" ); document.write( "Check solution by finding the distance of each:
\n" ); document.write( "16(2+3) = 80
\n" ); document.write( "40(2) = 80 miles also \n" ); document.write( "
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