document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061532>Question 1061532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Nora leaves Town A and walks towards Town B at a speed of 100m/min. At the same time , Kate and Lixin walk from Town B towards Town A at a speed of 80mm/min and 75m/min respectively. If Nora meets Lixin 6 minutes after passing Kate, find the distance between Town A and Town B.\r<BR>\n" );
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document.write( "Please help me this one!! I need it now!! Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #838346 by </B><A HREF=/tutors/aboutme.mpl?userid=Sam91><B>Sam91(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Sam91><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=838346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d be the distance (in meters) between cities A and B.<BR>\n" );
document.write( "Time in minutes and speed in meters per minute (m/ min)\r<BR>\n" );
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document.write( "Using formula, distance = speed *  time <BR>\n" );
document.write( "                  d= v * t\r<BR>\n" );
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document.write( "let @ time t minutes Nora meets Kate.\r<BR>\n" );
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document.write( "         d= 100*t + 80*t   <BR>\n" );
document.write( "         d= 180* t   (1) <BR>\n" );
document.write( "('d' is point @ kate and nora meet each other= Distance covered by Nora + distance covered Kate)\r<BR>\n" );
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document.write( "Similarly, @ time (t+6) minues Nora meets Lixin\r<BR>\n" );
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document.write( "        d= 100*(t+6) + 75*(t+6)   ( here (t+6) is common)<BR>\n" );
document.write( "        d= 175*(t+6)   <BR>\n" );
document.write( "        d= 175*t + 1050    (2) \r<BR>\n" );
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document.write( "Equating (1) and (2)  <BR>\n" );
document.write( "                   d   =   d \r<BR>\n" );
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document.write( "                  180 t = 175 t+ 1050<BR>\n" );
document.write( "On simplifying,<BR>\n" );
document.write( "                  180t - 175t = 1050\r<BR>\n" );
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document.write( "                           5t = 1050<BR>\n" );
document.write( "                            t=210 minutes\r<BR>\n" );
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document.write( "@ time = 210 minutes Nora met Kate<BR>\n" );
document.write( "Also,@ time (210+6=) 216 minutes Nora met Lixin\r<BR>\n" );
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document.write( "Using, the value to t and substituting in equation (1)<BR>\n" );
document.write( "                      d= 180* 210 m (here minutes will be cancelled by minutes)\r<BR>\n" );
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document.write( "                  d= 18*21*100 m = 37800 metrea\r<BR>\n" );
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document.write( "The distance between the cities A and B is 37800 meters. </SPAN>\n" );
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