document.write( "Question 1203084: Show that if |x+3| < 1/2 , then |4x+13| < 3 \n" ); document.write( "
Algebra.Com's Answer #838345 by Edwin McCravy(20086)\"\" \"About 
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document.write( "|x+3| < 1/2 , then |4x+13| < 3\r\n" );
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document.write( "\"abs%28x%2B3%29%3C1%2F2\"\r\n" );
document.write( "By definition,\r\n" );
document.write( "\"-1%2F2%3Cx%2B3%3C1%2F2\"\r\n" );
document.write( "Subtract 3 from all 3 sides\r\n" );
document.write( "\"-1%2F2-3%3Cx%2B3-3%3C1%2F2-3\"\r\n" );
document.write( "Simplify\r\n" );
document.write( "\"-7%2F2%3Cx%3C-5%2F2\"\r\n" );
document.write( "Multiply all 3 sides by 4\r\n" );
document.write( "\"-14%3C4x%3C-10\"\r\n" );
document.write( "Add 13 to all 3 sides\r\n" );
document.write( "\"-14%2B13%3C4x%2B13%3C-10%2B13\"\r\n" );
document.write( "Simplify\r\n" );
document.write( "\"-1%3C4x%2B13%3C3\"\r\n" );
document.write( "Since -3 < -1\r\n" );
document.write( "\"-3%3C4x%2B13%3C3\"\r\n" );
document.write( "By definition,\r\n" );
document.write( "\"abs%284x%2B13%29%3C3\"\r\n" );
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document.write( "Edwin
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