document.write( "Question 1203080: a trucking firm suspects that the mean lifetime of a certain tire it uses is less than 34,000 miles. To check the claim, the firm randomly selects and tests 54 of these tires and gets a mean lifetime of 33,390 miles with a standard deviation of 1200 miles. At α = 0.05
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Algebra.Com's Answer #838340 by Theo(13342)\"\" \"About 
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population mean = 34000 = m
\n" ); document.write( "sample size = 54 = n
\n" ); document.write( "sample mean = 33390 = x
\n" ); document.write( "sample standard deviation = 1200 = d
\n" ); document.write( "one tailed confidence interval is .95 with .05 tail on the left end of it.
\n" ); document.write( "it's a one tail confidence interval because the test is to determine if the mean lifetime of the sample is less than the population mean.
\n" ); document.write( "since the standad deviation is taken from the sample, the t-test is used.
\n" ); document.write( "the standard error of the test is equal to the standard deviation of the sample divided by the square root of the sample size = d / sqrt(n) = 1200 / sqrt(54) = 163.2993162.
\n" ); document.write( "the t-score formula is t = (x-m)/s which is equal to (33390 - 34000) / 163.2993162 = -3.73547.
\n" ); document.write( "the area to the left of that t-score, with 53 degrees of freedom, is equal to .00029828.
\n" ); document.write( "this is considerably less than the critical p-value of .05.
\n" ); document.write( "also, the critical t-score at 95% left side one tailed confidence interval is equal to t = -1.674116.
\n" ); document.write( "the test t-score of -3.73547 is greater than this, supporting the conclusion that the results of the test are significant.
\n" ); document.write( "this means that the mean lifetime of those certain tires can be assumed to actually be less than the 34000 originally stated.
\n" ); document.write( "this is what the t-test results look like on a graph.\r
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