document.write( "Question 1203078: A dairy farmer wants to mix a 20%
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document.write( " protein supplement and a standard 10%
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document.write( " protein ration to make 1200
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document.write( " pounds of a high-grade 15%
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document.write( " protein ration. How many pounds of each should he use? \n" );
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Algebra.Com's Answer #838331 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! A dairy farmer wants to mix a 20% protein supplement \n" ); document.write( "and a standard 10% protein ration \n" ); document.write( "to make 1200 pounds of a high-grade 15% \n" ); document.write( "protein ration. How many pounds of each should he use? \n" ); document.write( "~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "x pounds of the 20% protein supplement and\r\n" ); document.write( "(1200-x) pounds of a standard 10% protein ration.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The protein total mass equation is\r\n" ); document.write( "\r\n" ); document.write( " 0.2x + 0.10*(1200-x) = 0.15*1200\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify, solve and find x\r\n" ); document.write( "\r\n" ); document.write( " 0.2x + 120 - 0.1x = 180\r\n" ); document.write( "\r\n" ); document.write( " 0.2x - 0.1x = 180 - 120\r\n" ); document.write( "\r\n" ); document.write( " 0.1x = 60\r\n" ); document.write( "\r\n" ); document.write( " x = 60/0.1 = 600.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. 600 pounds of the 20% protein supplement and 1200-600 = 600 pounds of the standard 10% protein ration.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It also can be solved MENTALLY (~ guessed from the first glance), if to notice that \n" ); document.write( "15% of the resulting protein concentration is half-way between 10% and 20% of the \n" ); document.write( "input ingredients.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |