document.write( "Question 1203031: If 3 books are picked from the shelf containing 5 novels 3 books of poems and a dictionary what is the prbability that the dictionary is selected.
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document.write( "2) 2 novels and 1 book of poem are selected \n" );
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Algebra.Com's Answer #838267 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "In addition to the solution to the first problem from the other tutor, using nCr numbers, here are two other more elementary ways to solve that one. \n" ); document.write( "These alternative methods only work for relatively simple problems like this one; however, they are useful methods for many similar problems. \n" ); document.write( "(1) Pick the books one at a time and find the probability that the dictionary is NOT selected; then the probability that it IS selected is 1 minus that probability. \n" ); document.write( "P(not selected first) = 8/9 \n" ); document.write( "P(not selected first and not selected second) = (8/9)(7/8) = 7/9 \n" ); document.write( "P(not selected first and not selected second and not selected third) = (8/9)(7/8)(6/7) = 6/9 = 2/3 \n" ); document.write( "P(IS selected first or second or third) = 1 - 2/3 = 1/3 \n" ); document.write( "(2) Pick the books one at a time and find the probability that the dictionary is selected either first or second or third. \n" ); document.write( "P(picked first) = 1/9 \n" ); document.write( "P(not picked first; picked second) = (8/9)(1/8) = 1/9 \n" ); document.write( "P(not picked first or second; picked third) = (8/9)(7/8)(1/7) = 1/9 \n" ); document.write( "P(picked first or second or third) = 1/9 + 1/9 + 1/9 = 3/9 = 1/3 \n" ); document.write( "Note solving your second problem by either of these methods would be very tedious because of the many different sequences in which the 2 novels and 1 book of poems could be selected. The nCr method shown by the other tutor is far more efficient for this problem. \n" ); document.write( " \n" ); document.write( " |