document.write( "Question 1203028: By volume, one alloy is 60, copper, 30, zinc, and 10, nickel. A second alloy has percents of 50,
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document.write( "30, and 20, respectively. A third alloy is 30, copper and 70, nickel. How much of each alloy is
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document.write( "needed to make 100 cm3 of a resulting alloy with percents of 40, 15, and 45, respectively? \n" );
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Algebra.Com's Answer #838251 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x = cm^3 of alloy A \n" ); document.write( "y = cm^3 of alloy B \n" ); document.write( "z = cm^3 of alloy C \n" ); document.write( "The copper equation: 60% of x, plus 50% of y, plus 30% of z, is equal to 40% of the total 100 cm^3: \n" ); document.write( " \n" ); document.write( "The zinc equation: 50% of x, plus 30% of y, and none of z, is equal to 15% of the total 100 cm^3: \n" ); document.write( " \n" ); document.write( "The nickel equation: 30% of x, plus 20% of y, plus 70% of z, is equal to 45% of the total 100 cm^3: \n" ); document.write( " \n" ); document.write( "For an algebraic solution, since equation [2] involves only x and y, eliminate z between equations [1] and [3] to get a second equation involving only x and y. Then that pair of equations can be solved for x and y, leading to a solution of the whole problem. \n" ); document.write( "Multiply [1] by 7 and [3] by 3 and find the difference to eliminate z: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now solve [2] and [4]. \n" ); document.write( "Multiply [2] by 33 and [4] by 5.... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: none of alloy A, and 50 cm^3 each of alloys B and C \n" ); document.write( " \n" ); document.write( " |