document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1203007>Question 1203007</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In triangle ABC . B = 60 deg c = 7cm and a = 10cm If M is the midpoint of BC find without using tables, the lengths of AM and AC. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #838224 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=838224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In triangle ABC . B = 60 deg c = 7cm and a = 10cm If M is the midpoint of BC find without using tables, the lengths of AM and AC.<BR>\n" );
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document.write( "b = AC<BR>\n" );
document.write( "Use the Cosine Law to find b<BR>\n" );
document.write( "b^2 = a^2 + c^2 - 2ac*cos(60)<BR>\n" );
document.write( "b^2 = 100 + 49 - 2*10*7*0.5 = 149 - 70 = 79<BR>\n" );
document.write( "b = sqrt(79)<BR>\n" );
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document.write( "Use the Law of Sines to find angle A:<BR>\n" );
document.write( "sin(B)/b = sin(A)/a<BR>\n" );
document.write( "sin(A) = a*sin(B)/b = 10*sin(60)/sqrt(79)<BR>\n" );
document.write( "sin(A) = 0.97435<BR>\n" );
document.write( "A = 77 degs<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Angle A = 180 - (77+60) = 43 degs<BR>\n" );
document.write( "A/2 = 21.5 degs<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Use the Cosine Law to find AM<BR>\n" );
document.write( " </SPAN>\n" );
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