document.write( "Question 1203006: 2log10^x+log10^3=log75 \n" ); document.write( "
Algebra.Com's Answer #838222 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
Many or some algebraic steps, reaching at \"x=log%28%2875%29%29%2F20-3%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "or as \"x=%28log%28%2875%29%29-30%29%2F20\"
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