document.write( "Question 1202999: In a town, Chief X resides 60m away on a bearing of 057° from the palace P, while Chief y resides on a bearing of 150° from the same palace P. The residence of X and Y are 180m apart.\r
\n" ); document.write( "\n" ); document.write( "(a) Illustrate the information in a diagram.\r
\n" ); document.write( "\n" ); document.write( " Find, correct to three significant figures, the:\r
\n" ); document.write( "\n" ); document.write( "(i) bearing of X from Y;\r
\n" ); document.write( "\n" ); document.write( "(ii) distance between P and Y.
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Algebra.Com's Answer #838214 by math_tutor2020(3821)\"\" \"About 
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\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "This is one way to draw the diagram.
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\n" ); document.write( "\n" ); document.write( "The triangle XPY is shown above with extra helper points A,B,C.\r
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\n" ); document.write( "\n" ); document.write( "Point A is directly north of P.
\n" ); document.write( "Point A is useful to form the angles APX = 57 and APY = 150
\n" ); document.write( "These are the bearing angles.
\n" ); document.write( "The bearing angles have direct north as the starting direction, and then you turn clockwise toward the east when increasing the angles.\r
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\n" ); document.write( "\n" ); document.write( "note:
\n" ); document.write( "(angle APX) + (angle XPY) = angle APY
\n" ); document.write( "57° + 93° = 150°\r
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\n" ); document.write( "\n" ); document.write( "Point B is north of Y to help set up angle BYX. See the next section below.\r
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\n" ); document.write( "\n" ); document.write( "Point C is south of P so we can form angle CPY, which will help determine angle CYP.\r
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\n" ); document.write( "\n" ); document.write( "For the next two parts, I'll give hints.\r
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\n" ); document.write( "\n" ); document.write( "Part (i)\r
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\n" ); document.write( "\n" ); document.write( "You'll need to...
  1. Determine angle BYX
  2. Subtract that angle from 360 to find the reflex angle, so you can determine the bearing of X from Y.
Note that
\n" ); document.write( "(angle CYP) + (angle PYX) + (angle BYX) = 90\r
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\n" ); document.write( "\n" ); document.write( "Angle CYP is complementary to angle CPY = 30 shown in the diagram.
\n" ); document.write( "i.e.
\n" ); document.write( "(angle CPY) + (angle CYP) = 90
\n" ); document.write( "30 + (angle CYP) = 90
\n" ); document.write( "I'll let you finish this part.\r
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\n" ); document.write( "\n" ); document.write( "Angle PYX is determined through the law of sines
\n" ); document.write( "Focus on triangle XPY to say:
\n" ); document.write( "sin(P)/XY = sin(Y)/PX
\n" ); document.write( "sin(93)/180 = sin(Y)/60
\n" ); document.write( "I'll let you finish this part.
\n" ); document.write( "This will determine angle PYX.\r
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\n" ); document.write( "\n" ); document.write( "After determining angles CYP and PYX, you'll have enough info to determine angle BYX.\r
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\n" ); document.write( "\n" ); document.write( "After finding angle BYX, subtract from 360.
\n" ); document.write( "The goal is to compute: 360 - (angle BYX)
\n" ); document.write( "so you can find the bearing of X from Y.\r
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\n" ); document.write( "\n" ); document.write( "To answer part (ii), you can use either the law of sines or law of cosines to find the distance from P to Y.
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