document.write( "Question 1202985: If the mean height of bonsai trees is 52 cm with a standard deviation of 10 cm, 95% of the trees are between _________ and _________.
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document.write( " -62
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document.write( "-82
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document.write( "-32
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document.write( "-42
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document.write( "-22
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document.write( "-72 \n" );
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Algebra.Com's Answer #838199 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 95% of the trees are between 32 cm and 72 cm \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The Empirical Rule says that roughly 95% of the normally distributed population is within 2 standard deviations of the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract off 2 copies of the standard deviation from the mean. \n" ); document.write( "mean - 2*standardDev = 52 - 2*10 = 32 \n" ); document.write( "That's the lower boundary.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then add 2 copies of the standard deviation to the mean. \n" ); document.write( "mean + 2*standardDev = 52 + 2*10 = 72 \n" ); document.write( "That's the upper boundary.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can say P(32 < x < 72) = 0.95 approximately. \n" ); document.write( "In other words, the area under this particular normal distribution curve between x = 32 and x = 72 is roughly 0.95 \n" ); document.write( " \n" ); document.write( " |