document.write( "Question 1202976: An absent-minded secretary randomly puts four letters into four envelopes. What is the probability that at least one of the letters will be in the correct envelopes. \n" ); document.write( "
Algebra.Com's Answer #838197 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The response from the other tutor arrives at the correct answer only by chance; the method used is faulty. If we use that method on the problem with only 3 envelopes, the answer we get is \n" ); document.write( "3C1/3!+3C2/3!+3C3/3! = 3/6 + 3/6 + 1/6 = 7/6 \n" ); document.write( "which of course is not a valid number for a probability. \n" ); document.write( "The probability that at least one letter gets into the right envelope is 1, minus the probability that none of them get in the right envelope. \n" ); document.write( "If no letter gets in the right envelope, we have a derangement -- an arrangement in which none of the letters are in the right place. The number of derangements of 4 items is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(N.B. -- Do an internet search on \"derangement\" if you want to try to understand that formula....) \n" ); document.write( "Since there are 4! = 24 possible arrangements of the 4 letters, the probability that we have a derangement (none of the letters is in the right envelope) is 9/24 = 3/8 \n" ); document.write( "So the probability that at least one letter gets in the right envelope is 1-3/8 = 5/8. \n" ); document.write( "ANSWER: 5/8 \n" ); document.write( " \n" ); document.write( " |