document.write( "Question 1202976: An absent-minded secretary randomly puts four letters into four envelopes. What is the probability that at least one of the letters will be in the correct envelopes. \n" ); document.write( "
Algebra.Com's Answer #838197 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The response from the other tutor arrives at the correct answer only by chance; the method used is faulty. If we use that method on the problem with only 3 envelopes, the answer we get is

\n" ); document.write( "3C1/3!+3C2/3!+3C3/3! = 3/6 + 3/6 + 1/6 = 7/6

\n" ); document.write( "which of course is not a valid number for a probability.

\n" ); document.write( "The probability that at least one letter gets into the right envelope is 1, minus the probability that none of them get in the right envelope.

\n" ); document.write( "If no letter gets in the right envelope, we have a derangement -- an arrangement in which none of the letters are in the right place. The number of derangements of 4 items is

\n" ); document.write( "\"4%21%281-1%2F1%21%2B1%2F2%21-1%2F3%21%2B1%2F4%21%29\"
\n" ); document.write( "\"24%281-1%2B1%2F2-1%2F6%2B1%2F24%29\"
\n" ); document.write( "\"12-4%2B1+=+9\"

\n" ); document.write( "(N.B. -- Do an internet search on \"derangement\" if you want to try to understand that formula....)

\n" ); document.write( "Since there are 4! = 24 possible arrangements of the 4 letters, the probability that we have a derangement (none of the letters is in the right envelope) is 9/24 = 3/8

\n" ); document.write( "So the probability that at least one letter gets in the right envelope is 1-3/8 = 5/8.

\n" ); document.write( "ANSWER: 5/8

\n" ); document.write( "
\n" ); document.write( "
\n" );