document.write( "Question 1202920: Eugene received many emails over the weekend. 2/7 of the emails were work related and 7/10 of the remaining mails were from friends. 3/4 of the remaining emails were advertisements. Given that Eugene received 14 more emails from work than from advertisements, how many emails did he get over the weekend?
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Algebra.Com's Answer #838123 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Fraction that were work related: 2/7

\n" ); document.write( "Fraction remaining: 1 - 2/7 = 5/7

\n" ); document.write( "Fraction that were from friends: 7/10 of the remaining = (7/10)(5/7) = 5/10 = 1/2

\n" ); document.write( "Fraction remaining: 1 - 2/7 - 1/2 = 14/14 - 4/14 - 7/14 = 3/14

\n" ); document.write( "Fraction that were advertisements: 3/4 of the remaining = (3/4)(3/14) = 9/56

\n" ); document.write( "He got 14 more emails from work than from advertisements:

\n" ); document.write( "(2/7)x - (9/56)x = 14
\n" ); document.write( "(16/56) - (9/56)x = 14
\n" ); document.write( "(7/56)x = 14
\n" ); document.write( "(1/8)x = 14
\n" ); document.write( "x = 14*8 = 112

\n" ); document.write( "ANSWER: 112

\n" ); document.write( "CHECK:
\n" ); document.write( "total: 112
\n" ); document.write( "work: (2/7)(112) = 32
\n" ); document.write( "other: 112-32 = 80
\n" ); document.write( "friends: (7/10)(80) = 56
\n" ); document.write( "other: 80-56 = 24
\n" ); document.write( "advertisements: (3/4)(24) = 18
\n" ); document.write( "work minus advertisements: 32-18 = 14

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