document.write( "Question 1202898: If xy>0 and xz<0, which of the following statements must be true?\r
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document.write( "I. x+y+z>0
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document.write( "II. xyz<0
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document.write( "III. xy+xz+yz>0\r
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document.write( "(A) I only
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document.write( "(B) II only
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document.write( "(C) III only
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document.write( "(D) II and III only
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document.write( "(E) None of the above \n" );
document.write( "
Algebra.Com's Answer #838108 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "If xy > 0 and xz < 0, which of the following statements must be true? \n" ); document.write( "I. x + y + z > 0 \n" ); document.write( "II. xyz < 0 \n" ); document.write( "III. xy + xz + yz > 0 \n" ); document.write( "(A) I only \n" ); document.write( "(B) II only \n" ); document.write( "(C) III only \n" ); document.write( "(D) II and III only \n" ); document.write( "(E) None of the above \n" ); document.write( "~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " The answer is (E).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " To prove it, it is enough to provide couner-examples to cases (I), (II) and (III) separately.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Counter-example to (I) : x= -1, y= -1, z= 1.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Counter-example to (II) : x= -1, y= -1, z= 1.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Counter-example to (III): x= -1, y= -1, z= 1.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved, with explanations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |