document.write( "Question 1202898: If xy>0 and xz<0, which of the following statements must be true?\r
\n" ); document.write( "\n" ); document.write( "I. x+y+z>0
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\n" ); document.write( "\n" ); document.write( "(A) I only
\n" ); document.write( "(B) II only
\n" ); document.write( "(C) III only
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\n" ); document.write( "(E) None of the above
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Algebra.Com's Answer #838108 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "If xy > 0 and xz < 0, which of the following statements must be true?
\n" ); document.write( "I. x + y + z > 0
\n" ); document.write( "II. xyz < 0
\n" ); document.write( "III. xy + xz + yz > 0
\n" ); document.write( "(A) I only
\n" ); document.write( "(B) II only
\n" ); document.write( "(C) III only
\n" ); document.write( "(D) II and III only
\n" ); document.write( "(E) None of the above
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\n" ); document.write( "\n" ); document.write( "        The answer is  (E).\r
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\n" ); document.write( "\n" ); document.write( "        To prove it,  it is enough to provide couner-examples to cases  (I),  (II)  and  (III)  separately.\r
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document.write( "Counter-example to (I)  :  x= -1, y= -1, z= 1.\r\n" );
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document.write( "Counter-example to (II) :  x= -1, y= -1, z= 1.\r\n" );
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document.write( "Counter-example to (III):  x= -1, y= -1, z= 1.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved,  with explanations.\r
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