document.write( "Question 1202823: ighTech Incorporated randomly tests its employees about company policies. Last year in the 510 random tests conducted, 16 employees failed the test.\r
\n" ); document.write( "\n" ); document.write( "a. What is the point estimate of the population proportion that failed the test?
\n" ); document.write( "b. What is the margin of error for a 95% confidence interval estimate?
\n" ); document.write( "c. Compute the 95% confidence interval for the population proportion.
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Algebra.Com's Answer #838056 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
best i can make out of this based on what's given is:\r
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\n" ); document.write( "\n" ); document.write( "p = mean failure rate = 16 / 510 = .03137.
\n" ); document.write( "q = (1 - p) - (1 - 16 / 510) = (1 - .03137) = .96863.\r
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\n" ); document.write( "\n" ); document.write( "point estimate of the population proportion that failed the test is 16 / 510 = .03137 rounded to 5 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "standard error for a proportion is equal to sqrt (p * q / n) which is equal to sqrt(.03137 * .96863 / 510) = .00772.\r
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\n" ); document.write( "\n" ); document.write( "margin of error for 95% confidence interval of the mean failure rate would be based on the critical z-score of plus or minus 1.96.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes 1.96 = (x - .03137) / .00772.
\n" ); document.write( "solve for (x - .03137) to get:
\n" ); document.write( "(x - .03137) = 1.96 * .00772 = .01513.
\n" ); document.write( "that's your margin of error.\r
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\n" ); document.write( "\n" ); document.write( "solve for x in that same formula to get:
\n" ); document.write( "x = 1.96 * .00772 + .03157 = .0465012.
\n" ); document.write( "that would be the high side of the interval.\r
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\n" ); document.write( "\n" ); document.write( "the low side of the interval would be equal to -1.96 * .00772 + .031357 = .01623388.\r
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\n" ); document.write( "\n" ); document.write( "answers to your questions would be, as far as i can tell.\r
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\n" ); document.write( "\n" ); document.write( "a. What is the point estimate of the population proportion that failed the test?
\n" ); document.write( ".03137\r
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\n" ); document.write( "\n" ); document.write( "b. What is the margin of error for a 95% confidence interval estimate?
\n" ); document.write( ".01513\r
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\n" ); document.write( "\n" ); document.write( "c. Compute the 95% confidence interval for the population proportion.
\n" ); document.write( ".0162388 to .0465012.\r
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\n" ); document.write( "\n" ); document.write( "this is the best that i can do, based on what i know.
\n" ); document.write( "the mean failure rate was 16/510.
\n" ); document.write( "the 95% confidence interval was based on that as the mean.\r
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\n" ); document.write( "\n" ); document.write( "let me know is you have any questions.
\n" ); document.write( "theo
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