document.write( "Question 1202861: Jon had red and blue pencils. He put them into Boxes X and Y. Box X had 2 times as many pencils as Box Y. All the pencils in Box X were red. In Box Y, the ratio of the number of red pencils to the number of blue pencils was 8:1.
\n" ); document.write( "(a) What fraction of the total number of pencils in both boxes were blue? Give your answer in the simplest form.
\n" ); document.write( "(b) There were 90 more red pencils in Box X than in Box Y. How many blue pencils were there altogether? \n" ); document.write( "

Algebra.Com's Answer #838035 by ikleyn(52803) $\"\"$ $\"About$

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\n" ); document.write( "Jon had red and blue pencils. He put them into Boxes X and Y.
\n" ); document.write( "Box X had 2 times as many pencils as Box Y.
\n" ); document.write( "All the pencils in Box X were red.
\n" ); document.write( "In Box Y, the ratio of the number of red pencils to the number of blue pencils was 8:1.
\n" ); document.write( "(a) What fraction of the total number of pencils in both boxes were blue?
\n" ); document.write( "Give your answer in the simplest form.
\n" ); document.write( "(b) There were 90 more red pencils in Box X than in Box Y.
\n" ); document.write( "How many blue pencils were there altogether?
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document.write( "Let \"b\" be the number of blue pencils in box Y.\r\n" );
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document.write( "Then the number of red pencils in box Y is 8b,\r\n" );
document.write( "     the number of all pencils in box Y is b + 8b = 9b,\r\n" );
document.write( "and  the number of red pencils in box X is 2*(9b) = 18b.\r\n" );
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document.write( "Now the answer to question (a) is   =  = .\r\n" );
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document.write( "For (b), we have 8b red pencils in box Y and 18b red pencils in box X.\r\n" );
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document.write( "From the problem, we have this equation\r\n" );
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document.write( "    18b - 8b = 90\r\n" );
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document.write( "      10b    = 90\r\n" );
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document.write( "        b    = 90/10 = 9.\r\n" );
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document.write( "So, there are 9 blue pencils in box Y, which means that there are 9 blue pencils in both boxes, altogether.\r\n" );
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