document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115188>Question 115188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fence builder wishes to determine the cost of fencing a rectangular yard with a perimeter of 68 feet.  Suppose that the length of the yard is 4 feet less than its width.  Find the length and width of the room. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83800 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W-4<BR>\n" );
document.write( "PERIMETER=2W+2L<BR>\n" );
document.write( "2W+2(W-4)=68<BR>\n" );
document.write( "2W+2W-8=68<BR>\n" );
document.write( "4W=68+8<BR>\n" );
document.write( "4W=76<BR>\n" );
document.write( "W=76/4 <BR>\n" );
document.write( "W=19 FEET IS THE WIDTH<BR>\n" );
document.write( "L=19-4=15 FEET FOR THE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*19+2*15=68<BR>\n" );
document.write( "38+30=68<BR>\n" );
document.write( "68=68 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );