document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202822>Question 1202822</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pharmaceutical companies promote their prescription drugs using television advertising. In a survey of 112 randomly sampled television viewers, 14 indicated that they asked their physician about using a prescription drug they saw advertised on TV.\r<BR>\n" );
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document.write( "a. What is the point estimate of the population proportion? <BR>\n" );
document.write( "b. What is the margin of error for a 95% confidence interval estimate? (Round \"z-scores\" and round your final answers to 2 decimal places.)<BR>\n" );
document.write( "c. Compute the 95% confidence interval for the population proportion. (Round \"z-scores\" to 2 decimal places and round your answers to 3 decimal places.)<BR>\n" );
document.write( " Confidence interval for the proportion mean is between ___ and ___. \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837992 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pharmaceutical companies promote their prescription drugs using television advertising. In a survey of 112 randomly sampled television viewers, 14 indicated that they asked their physician about using a prescription drug they saw advertised on TV.<BR>\n" );
document.write( "a. What is the point estimate of the population proportion?\r<BR>\n" );
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document.write( "The sample proportion is 14/112 or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%280.125%29 ALIGN=MIDDLE  ALT=\"highlight%280.125%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "b. What is the margin of error for a 95% confidence interval estimate? (Round \"z-scores\" and round your final answers to 2 decimal places.)\r<BR>\n" );
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document.write( "Since P(-1.96 < Z < 1.96) = 0.95 where Z is a Standard Normal random variable, then the margin of error is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.96%2Asqrt%280.125%2A%281-0.125%29%2F112%29 ALIGN=MIDDLE  ALT=\"1.96%2Asqrt%280.125%2A%281-0.125%29%2F112%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%280.06%29 ALIGN=MIDDLE  ALT=\"highlight%280.06%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "c. Compute the 95% confidence interval for the population proportion. (Round \"z-scores\" to 2 decimal places and round your answers to 3 decimal places.)<BR>\n" );
document.write( "Confidence interval for the proportion mean is between ___ and ___.\r<BR>\n" );
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document.write( "We use parts a and b to answer part-c.<BR>\n" );
document.write( "lower limit = 0.125 - 0.061 = 0.064<BR>\n" );
document.write( "upper limit = 0.125 + 0.061 = 0.186<BR>\n" );
document.write( "Answers: between 0.064 and 0.186 </SPAN>\n" );
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