document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115179>Question 115179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A service station wishes to mix 40 L of a 78% antifreeze solution. How many litres of a 75% solution and a 90% solution should be used in forming the mixture? ( using two unknowns, write two equations and solve.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83798 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .9X+.75(40-X)=40*.78<BR>\n" );
document.write( ".9X+30-.75X=31.2<BR>\n" );
document.write( ".15X=31.2-30<BR>\n" );
document.write( ".15X=1.2<BR>\n" );
document.write( "X=1.2/.15<BR>\n" );
document.write( "X=8L OF 90% IS NEEDED.<BR>\n" );
document.write( "40-8=32L OF 75% IS NEEDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".9*8+.75*32=40*.78<BR>\n" );
document.write( "7.2+24=31.2<BR>\n" );
document.write( "31.2=31.2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );