document.write( "Question 1202812: Solve the system of linear equations, using the Gauss-Jordan elimination method. (If there is no solution, enter NO SOLUTION. If there are infinitely many solutions, express your answer in terms of the parameters t and/or s.)\r
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document.write( "x + 2y + z = −2
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document.write( "−2x − 3y − z = 3
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document.write( "4x + 8y + 4z = −8\r
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document.write( "(x, y, z) = \r
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document.write( "I'm very confused to how I would start to do this. Please give steps then a final answer so that I can check my work. Please and thank you.\r
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Algebra.Com's Answer #837963 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You can't check your work by looking at my solution, because we can easily take very different paths to the answer. \n" ); document.write( "Here is one way to get to the solution to the system of equations. \n" ); document.write( "The original matrix, directly from the system of equations: \n" ); document.write( " \n" ); document.write( "I can see immediately that this system is not going to have a unique solution, because the 3rd row of the matrix is exactly 4 times the 1st row. One of the operations we can perform is to multiply one row by a constant, so the first thing I would do in this example is multiply the 3rd row by 1/4: \n" ); document.write( " \n" ); document.write( "Now I am ready to start on the standard sequence of steps to find the solution. \n" ); document.write( "First step: get \"1\" in row 1 column 1 if it is not already there. Row 1 column 1 is already 1, so we don't need to do anything here. \n" ); document.write( "Next step: Use the \"1\" in row 1 column 1 to get \"0\" in every other row in column 1 by multiplying the first row by a constant and adding it to another row. \n" ); document.write( "Get \"0\" in row 2 column 1 by multiplying row 1 by 2 and adding it to row 2; get a \"0\" in row 3 column 1 by multiplying row 1 by -1 and adding it to row 3. \n" ); document.write( " \n" ); document.write( "Note the row of all \"0\" in row 3 is because in the previous matrix rows 3 and 1 were identical. \n" ); document.write( "Next step: get \"1\" in row 2 column 2 if it is not already there. Again that \"1\" is already there, so there is no work to do here. \n" ); document.write( "Next step: Use the \"1\" in row 2 column 2 to get \"0\" in every other row in column 2 by multiplying the second row by a constant and adding it to another row. \n" ); document.write( "Get a \"0\" in row 1 column 2 by multiplying row 2 by -2 and adding it to row 1. \n" ); document.write( " \n" ); document.write( "In a general problem, the next step would be to get a \"1\" in row 3 column 3. But since the third row is all \"0\", we have gone as far as we can performing operations on the matrix. \n" ); document.write( "The matrix we finish with tells us.... \n" ); document.write( "row 1: x-z = 0 \n" ); document.write( "row 2: y+z = -1 \n" ); document.write( "From this we get an infinite set of solutions using a parameter t: \n" ); document.write( "(1) x = t \n" ); document.write( "(2) x-z = 0; t-z = 0; so z = t \n" ); document.write( "(3) y+z = -1; y+t = -1; so y = -t-1 \n" ); document.write( "The family of solutions is defined by (x,y,z) = (t,-t-1,t) where t is any constant. \n" ); document.write( "To check the solution, we substitute these parametric expressions for x, y, and z in each of the original equations. \n" ); document.write( "(1) x+2y+z = (t)+(-2t-2)+t = -2 correct \n" ); document.write( "(2) -2x-3y-z = (-2t)+(3t+3)-t = 3 correct \n" ); document.write( "(3) 4x+8y+4z = (4t)+(-8t-8)+(4t) = -8 correct \n" ); document.write( " \n" ); document.write( " |